**We all have heard about Hydraulic lifts sometime in our life, but some of you may think that how it works or how to build one for ourselves.**

Today we are going to discuss about lifting cars using Hydraulics, which is based on Pascal concept.

Why understanding Hydraulics important ?

Hydraulics is a topic in applied science and engineering dealing with the mechanical properties of liquids. Fluid mechanics provides the theoretical foundation for hydraulics, which focuses on the engineering uses of fluid properties.

Concept :

Pascal’s law states that the pressure applied at one point of the liquid is transmitted equally in all direction. This principal is applied in hydraulic lift, for lifting heavy objects.

According to Law Force = Pressure x Area

P1 = P2 (since the pressures are equal throughout).

Since Pressure = Force/ Area

Formula becomes F1/A1 = F2/A2

Using above formula ,following example shows that how we can lift 10 pound force using 1 pound force only.

1 pound / 1 square inches = 10 pounds / 10 square inches

So, to lift a car we should produce force(F1) which is more than F2(car force)

F2 = F1 x A2 / A1

that is , if we have have two lift car with very little force(F2) , we need to maximize A2/A1 , which is only possible by maximizing A2(Area of 2) and minimizing A1(Area of 1) as shown in figure.

Today we are going to discuss about lifting cars using Hydraulics, which is based on Pascal concept.

Why understanding Hydraulics important ?

Hydraulics is a topic in applied science and engineering dealing with the mechanical properties of liquids. Fluid mechanics provides the theoretical foundation for hydraulics, which focuses on the engineering uses of fluid properties.

Concept :

Pascal’s law states that the pressure applied at one point of the liquid is transmitted equally in all direction. This principal is applied in hydraulic lift, for lifting heavy objects.

According to Law Force = Pressure x Area

P1 = P2 (since the pressures are equal throughout).

Since Pressure = Force/ Area

Formula becomes F1/A1 = F2/A2

Using above formula ,following example shows that how we can lift 10 pound force using 1 pound force only.

1 pound / 1 square inches = 10 pounds / 10 square inches

So, to lift a car we should produce force(F1) which is more than F2(car force)

F2 = F1 x A2 / A1

that is , if we have have two lift car with very little force(F2) , we need to maximize A2/A1 , which is only possible by maximizing A2(Area of 2) and minimizing A1(Area of 1) as shown in figure.

**Videos Links For Hydraulic Car Lift**

**http://www.google.co.in/url?sa=t&rct=j&q=&esrc=s&source=video&cd=1&ved=0CFEQtwIwAA&url=http%3A%2F%2Fwww.youtube.com%2Fwatch%3Fv%3DRC7ASx7chXA&ei=r9qIT_reFNHKrAeA2YW9Cw&usg=AFQjCNGefh2LnQoGp3MDviiQA0hsYYA66g&sig2=DkBMC9iebPm20n8gD_pmbg**

http://www.google.co.in/url?sa=t&rct=j&q=&esrc=s&source=video&cd=2&ved=0CFQQtwIwAQ&url=http%3A%2F%2Fwww.youtube.com%2Fwatch%3Fv%3DSksAfIlN7oM&ei=r9qIT_reFNHKrAeA2YW9Cw&usg=AFQjCNFhc21-ndghgmsSJjT4Z0M5IOgsIw&sig2=tcax8wVSpcc_4dPRG_lk4g

http://www.google.co.in/url?sa=t&rct=j&q=&esrc=s&source=video&cd=3&ved=0CFcQtwIwAg&url=http%3A%2F%2Fwww.youtube.com%2Fwatch%3Fv%3DknMIjFcLZik&ei=r9qIT_reFNHKrAeA2YW9Cw&usg=AFQjCNFFOzVrQ4FWFd5YfiblhT_01XRetg&sig2=bPFYti9rt1cFujcYjDWh3Q

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